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x(x+5)=x^-15
We move all terms to the left:
x(x+5)-(x^-15)=0
We multiply parentheses
x^2+5x-(x^-15)=0
We get rid of parentheses
x^2+5x-x^+15=0
We add all the numbers together, and all the variables
x^2+4x+15=0
a = 1; b = 4; c = +15;
Δ = b2-4ac
Δ = 42-4·1·15
Δ = -44
Delta is less than zero, so there is no solution for the equation
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